X^2-3x+4=2x^2-7x+12

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Solution for X^2-3x+4=2x^2-7x+12 equation: 



X^2-3X+4=2X^2-7X+12

We move all terms to the left:

X^2-3X+4-(2X^2-7X+12)=0

We get rid of parentheses

X^2-2X^2-3X+7X-12+4=0

We add all the numbers together, and all the variables

-1X^2+4X-8=0

a = -1; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-1)·(-8)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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